Geting the last inserted row for each CLIENT. How?

Hi,
I have a CLIENTS table with pk CLIENT_ID, and a CONVERSATIONS table where
CONV_ID and CLIENT_ID form the pk, there is another column CONVERSATION_DATE
where the conversation data is registered (and other columns).
Now I need to retrieve, for each client, the last N (for some clients,
eventually, less then N) conversations with one T-SQL statement.
Does anyone knows how to do this? Is it possible with T-SQL only?
Thanks.
See if this may work. If you also need to see clients without a
conversation, change the join to a left join.
select client.client_id, Conversations.conv_id
from client
inner join conversations on conversations.client_id = client.client_id
and conversations.conv_id in
(
select top 15 conv_id
from conversations
where client_id = client.client_id
order by conversation_date desc
)
A.Neves wrote:
> Hi,
> I have a CLIENTS table with pk CLIENT_ID, and a CONVERSATIONS table where
> CONV_ID and CLIENT_ID form the pk, there is another column CONVERSATION_DATE
> where the conversation data is registered (and other columns).
> Now I need to retrieve, for each client, the last N (for some clients,
> eventually, less then N) conversations with one T-SQL statement.
> Does anyone knows how to do this? Is it possible with T-SQL only?
> Thanks.
|||Didn't work,
but look here:
http://forums.microsoft.com/TechNet/ShowPost.aspx?PostID=917505&SiteID=17&mode=1
<Jochen.Markert@.fnf.com> escreveu na mensagem
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> See if this may work. If you also need to see clients without a
> conversation, change the join to a left join.
> select client.client_id, Conversations.conv_id
> from client
> inner join conversations on conversations.client_id = client.client_id
> and conversations.conv_id in
> (
> select top 15 conv_id
> from conversations
> where client_id = client.client_id
> order by conversation_date desc
> )
> A.Neves wrote:
>