I have the following code:
// Get timeout
Property itemTimeout = new Property();
itemTimeout.Name = "ReportTimeout";
Property[] props = new Property[1];
props[1] = itemName;
props[1] = itemTimeout;
Property[] itemProps = _rs.GetProperties(path_, props);
Problem I'm seeing is that this code returns no output array member
for the timeout if either the system default is being used or if there
is no timeout. How can I figure out which one it is then?Whoops - I tried to edit the code to take out some stuff that didn't
pertain to the problem. The code is actually good, looking like this:
Property itemTimeout = new Property();
itemTimeout.Name = "ReportTimeout";
Property[] props = new Property[1];
props[0] = itemTimeout;
Property[] itemProps = _rs.GetProperties(path_, props);
bspann <bspann@.discussions.microsoft.com> wrote in message news:<29B6FD22-E731-4486-9A9A-300BFD6D426E@.microsoft.com>...
> Derek,
> There is a problem with your code. In .NET all arrays are 0 based. So an
> array with one element should be arrayname[0]. So your code should look like
> this:
> Property[] props = new Property[1];
> props[0] = itemTimeout;
> Property[] itemProps = _rs.GetProperties(_path, props);
>
> "Derek Knudsen" wrote:
> > I have the following code:
> >
> > // Get timeout
> > Property itemTimeout = new Property();
> > itemTimeout.Name = "ReportTimeout";
> >
> > Property[] props = new Property[1];
> > props[1] = itemName;
> > props[1] = itemTimeout;
> >
> > Property[] itemProps = _rs.GetProperties(path_, props);
> >
> > Problem I'm seeing is that this code returns no output array member
> > for the timeout if either the system default is being used or if there
> > is no timeout. How can I figure out which one it is then?
> >|||More on this:
The GetProperty works fine, with -1 being returned if there is no timeout
and no value being returned if it uses the default setting. Problem was with
setting it to the default setting, which I had thought you could do by
setting the value to "0" (I can't find where I saw this). This throws an
"invalid value" exception. Anyway, solution was to not specify a value and
then it gets reset to "use default setting". Thanks.
"Derek Knudsen" wrote:
> Whoops - I tried to edit the code to take out some stuff that didn't
> pertain to the problem. The code is actually good, looking like this:
> Property itemTimeout = new Property();
> itemTimeout.Name = "ReportTimeout";
> Property[] props = new Property[1];
> props[0] = itemTimeout;
> Property[] itemProps = _rs.GetProperties(path_, props);
> bspann <bspann@.discussions.microsoft.com> wrote in message news:<29B6FD22-E731-4486-9A9A-300BFD6D426E@.microsoft.com>...
> > Derek,
> >
> > There is a problem with your code. In .NET all arrays are 0 based. So an
> > array with one element should be arrayname[0]. So your code should look like
> > this:
> >
> > Property[] props = new Property[1];
> > props[0] = itemTimeout;
> >
> > Property[] itemProps = _rs.GetProperties(_path, props);
> >
> >
> > "Derek Knudsen" wrote:
> >
> > > I have the following code:
> > >
> > > // Get timeout
> > > Property itemTimeout = new Property();
> > > itemTimeout.Name = "ReportTimeout";
> > >
> > > Property[] props = new Property[1];
> > > props[1] = itemName;
> > > props[1] = itemTimeout;
> > >
> > > Property[] itemProps = _rs.GetProperties(path_, props);
> > >
> > > Problem I'm seeing is that this code returns no output array member
> > > for the timeout if either the system default is being used or if there
> > > is no timeout. How can I figure out which one it is then?
> > >
>
Monday, March 26, 2012
GetProperties returns undeterminable timeout value
Labels:
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